[R6RS] integer-sqrt

Michael Sperber sperber at informatik.uni-tuebingen.de
Thu Dec 7 05:03:09 EST 2006

Wouldn't the name imply that the procedure accepts arbitrary integers,
rather than just exact ones?  (I guess the same ambiguity existed for
`exact-sqrt', but seemed less troublesome there.)

Cheers =8-} Mike
Friede, Völkerverständigung und überhaupt blabla

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